LPC Microcontrollers中的主题 Re: CRC32 with LPC1788

CRC32 with LPC1788

erenaud — Wed, 09 Jun 2021 16:19:52 GMT

Hello everyone !

I am currently trying to compute CRC32 checksum with a LPC1788.

Here is the functions I am using :

#define u32 unsigned long void Reg_InitCRC() { /* Standard CRC32 */ CRC_MODE = 0x00000036; /* CRC32 MPEG-2 */ // CRC_MODE = 0x00000002; CRC_SEED = 0xFFFFFFFF; } u32 REG_Calculate_CRC(u32 u32_Data) { u32 u32_CRC; CRC_WR_DATA = u32_Data; u32_CRC = CRC_SUM; return u32_CRC; }

Then, I am testing those function with this code :

u32 u32_data[4]; u32_data[0] = 0xAAAAAAAA; u32_data[1] = 0x69686968; u32_data[2] = 0x69686869; u32_data[3] = 0x12345678; u32 u32_res = 0; Reg_InitCRC(); u32_res = REG_Calculate_CRC(u32_data[0]); CRC_SEED = 0xFFFFFFFF; // Not really needed, just for safety u32_res = REG_Calculate_CRC(u32_data[1]); CRC_SEED = 0xFFFFFFFF; u32_res = REG_Calculate_CRC(u32_data[2]); CRC_SEED = 0xFFFFFFFF; u32_res = REG_Calculate_CRC(u32_data[3]);

So when doing this, I am observing a really strange behavior. When the input data is an u32 composed of identicals u8 (example : 0xAAAAAAAA) or "symetrical" u8 (0x12343412 and 0x69686869) the CRC output is correct (for both CRC32 and CRC32-MPEG2).
But when the data input is made of differents u8 (example : 0x12345678), the output is not what I am expecting at all.

Here's a table summing up my situation :

Input	My CRC32 output	Real CRC32 output	My MPEG2 output	Real MPEG2 output
0xAAAAAAAA	0xb596e05e	0xB596E05E	0x42fc4b29	0x42FC4B29
0x12343412	0xb0a58ffb	0xB0A58FFB	0x9db25e0f	0x9DB25E0F
0x69686869	0xb8e4c55e	0xB8E4C55E	0xff43f3da	0xFF43F3DA
0x12345678	0xaf6d87d2	0x4A090E98	0xad37d056	0xDF8A8A2B

When looking at this table, I finnally understood : if I want to have the "expected" CRC32, I have to reverse bytes (and not bits) in my input. So for the last line :

0x78563412 in my code (but actually computing CRC32 for 0x12345678)

0x4a090e98

0x4A090E98

0xdf8a8a2b

0xDF8A8A2B

So my question is : why do I have to switch the endianess of my u32 to find the expected result ?

Note : I am using this website to check CRC32.

Re: CRC32 with LPC1788

xiangjun_rong — Thu, 10 Jun 2021 03:37:16 GMT

How about using the init function:

void Reg_InitCRC() { /* Standard CRC32 */ CRC_MODE = 0x00000032; //instead of 0x36 /* CRC32 MPEG-2 */ // CRC_MODE = 0x00000002; CRC_SEED = 0xFFFFFFFF; }

I think that the BIT_RVS_WR should be cleared rather than being set.

Hope it can help you

XiangJun Rong

Re: CRC32 with LPC1788

erenaud — Thu, 10 Jun 2021 07:46:52 GMT

Hi,
First of all, thank you for your answer.
I think I already tried that, I will double check this afternoon.

But if I understand the documentation clearly, what BIT_RVS_WR is doing is reversing the bits order (and not the bytes).
So, 0x1234 5678 will be treated as 0x1E6A 2C48, am I right ?

(in binary)
00010010 00110100 01010110 01111000 --> 00011110 01101010 00101100 01001000

Re: CRC32 with LPC1788

xiangjun_rong — Thu, 10 Jun 2021 10:01:42 GMT

Hi,

I suppose that the CRC module of LPC1788 uses big endian format.

With PC CRC tools, if you input 0x78563412, the CRC32 output will be 0xaf6d87d2

With LOPC1788, if you input 0x12345678, the CRC32 output will be 0xaf6d87d2.

In conclusion, the CRC module of LPC1788 use big endian.

Hope it can help you

XiangJun Rong