topic Re: LPC55S69 : GINT0 and GINT1 in LPC Microcontrollers

LPC55S69 : GINT0 and GINT1

EugeneHiihtaja — Tue, 05 Nov 2019 09:44:06 GMT

Hello !

Do I understand right and any GPIO pin from group 0 or 1 can be included to GINT0 or 1.

So the same pin can't be in both GINTx but it port 0 pins can be part of GINT1 and vise versa.

Is this so.

But if I select edge sensitivity of all pins what are part of GINT0 group, can I select falling edge or rising edge

for each pin individually or for all of them ?

Regards,

Eugene

Re: LPC55S69 : GINT0 and GINT1

Alice_Yang — Wed, 06 Nov 2019 10:50:32 GMT

Hello Eugene Hiihtaja,

" any GPIO pin from group 0 or 1 can be included to GINT0 or 1."

-> Yes, any pins from PORT0 and PORT1 can be included to GINT0 and 1.

" the same pin can't be in both GINTx but it port 0 pins can be part of GINT1 and vise versa."

-> I think the same pin can be in both GINT0 and 1.

can I select falling edge or rising edge

for each pin individually or for all of them

-> Yes, you can config them individually. The PORT_POL register can config each pin polarity:

Have a great day,
TIC

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Re: LPC55S69 : GINT0 and GINT1

EugeneHiihtaja — Wed, 06 Nov 2019 20:01:16 GMT

Hello Alice !

It means I should include pin to both group if I would like to detect both edges.

Is this so ?

Regards,

Eugene

Re: LPC55S69 : GINT0 and GINT1

Alice_Yang — Wed, 13 Nov 2019 10:06:38 GMT

YES.

Re: LPC55S69 : GINT0 and GINT1

EugeneHiihtaja — Wed, 13 Nov 2019 11:11:41 GMT

Hi Alice !

For some reason it dosn't work like this. Please look y request : LPC55S69 : GINTx, detect both edges

If one pin is included to both GINTx it works, but if more, only falling edge starts to work.

May be special powermanagement API should be called ?

But for me it is blocker.

I need to find out reason and see if ISP,SW2,SW3 on EVK can be programmed in way that all edges are detected for 3 pins at list.

Can https://community.nxp.com/thread/517579 be prioritized some how ?

Regards,

Eugene

Re: LPC55S69 : GINT0 and GINT1

Alice_Yang — Tue, 19 Nov 2019 08:36:26 GMT

Hello Eugene,

There will other people help you on that thread.