why this is happen in kea128?

D_pengF — Thu, 07 Dec 2023 10:43:45 GMT

#define KBI_PE_KBIPE(x) (((uint32_t)(((uint32_t)(x))<<KBI_PE_KBIPE_SHIFT))&KBI_PE_KBIPE_MASK)
KBI1_PE |= KBI_PE_KBIPE(0x10);
why can Enable KBI1 channel 4(PTE4)?

Re: why this is happen in kea128?

RaRo — Fri, 08 Dec 2023 16:56:34 GMT

Hello @D_pengF,

According to the KEA128 Sub-Family Reference Manual the KBI assignment is as follows:

RaRo_1-1702054508667.png

[Excerpt of Table 3-45. KBI port assignment]

Now, let's check the line of your code:

KBI1_PE |= KBI_PE_KBIPE(0x10);

Remember that 0x10 means 0001 0000b which would indeed enable the CH4 (PTE4) as follows:

RaRo_2-1702054508670.png

[Section 35.4.1 KBI Pin Enable Register (KBIx_PE)]

You might find useful to take a look at the following information to help you with your development of KBI and KEA128:

KEA128 Sub-Family Reference Manual and,
AN4942: Getting Started with Kinetis EA series MCUs – Application Note.

Warm regards, Raul.

Re: why this is happen in kea128?

D_pengF — Fri, 19 Jan 2024 03:19:34 GMT

Dear Raul，thanks a lot

topic Re: why this is happen in kea128? in Kinetis Microcontrollers

why this is happen in kea128?

Re: why this is happen in kea128?

Re: why this is happen in kea128?