topic Re: Wrong baudrate flexcan demo "interrupt transfer" on FRDM-KV11Z SDK 2.7.0 in Kinetis Microcontrollers

Wrong baudrate flexcan demo "interrupt transfer" on FRDM-KV11Z SDK 2.7.0

robertoquilez — Mon, 11 May 2020 10:31:29 GMT

Hello,

When run the flexcan driver demo (nterrupt transfer) out of the box, the baudrate is supposed to be 1Mbps but at the oscilloscope we "see" only 138.9 KHz

How can we set the baudrate properly? We would like to get 250Kbps, but we are unable to get that baudrate.

Here CAN Bit Time Calculation we observe that no baud rate is compatible with 75MHz as core clock as configured by default in the demo.

Thank you in advance for your support,

Roberto

Re: Wrong baudrate flexcan demo "interrupt transfer" on FRDM-KV11Z SDK 2.7.0

kerryzhou — Tue, 12 May 2020 10:57:34 GMT

Hi Roberto Quilez,

You are using this code:

SDK_2.7.0_FRDM-KV11Z\boards\frdmkv11z\driver_examples\flexcan\interrupt_transfer

Right?

If the tool don't have the related 250Kbps, you can calculate by yourself, just find the proper PSEG1, PSEG2 and PROPSEG.

You can refer to the example to calculate it:

for e.g. 84M clock and 1M baud rate, the
quantum should be .e.g 14=(6+3+1)+4, so prescaler is 6. By default, quantum
is set to 10=(3+2+1)+4, because for most platforms e.g. 120M source clock/(1M
baud rate * 10) is an integer.

Anyway, tomorrow, I will help you to test it.

Kerry

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Re: Wrong baudrate flexcan demo "interrupt transfer" on FRDM-KV11Z SDK 2.7.0

kerryzhou — Wed, 13 May 2020 07:00:02 GMT

Hi Roberto Quilez,

Thanks for your question.

Today, I check the SDK code on my side, frdmkv11z_flexcan_interrupt_transfer. SDK2.7.0.

Find some code bugs, and I have modify it, it can transfer the 1Mbps and the 250Kbps now.

1. 1Mbps Modification points:

1)
/*#define PSEG1 5
#define PSEG2 2
#define PROPSEG 1
*/

#define PSEG1 4
#define PSEG2 1
#define PROPSEG 1

2) #define EXAMPLE_CAN_CLK_FREQ 10000000//CLOCK_GetFreq(kCLOCK_CoreSysClk)
or #define EXAMPLE_CAN_CLK_FREQ CLOCK_GetFreq(kCLOCK_Osc0ErClk)

Just select the external 10Mhz crystal as the clock source.

#define EXAMPLE_CAN_CLK_SOURCE (kFLEXCAN_ClkSrc0)

flexcanConfig.clkSrc = EXAMPLE_CAN_CLK_SOURCE;

Test Result:

2. Your desired 250Kbps modified points:

//250Kbps
#define PSEG1 4
#define PSEG2 1
#define PROPSEG 1

2) void FLEXCAN_GetDefaultConfig(flexcan_config_t *pConfig) in fsl_flexcan.c

void FLEXCAN_GetDefaultConfig(flexcan_config_t *pConfig)
{
/* Assertion. */
assert(NULL != pConfig);

/* Initializes the configure structure to zero. */
(void)memset(pConfig, 0, sizeof(*pConfig));

/* Initialize FlexCAN Module config struct with default value. */
pConfig->clkSrc = kFLEXCAN_ClkSrc0;
pConfig->baudRate = 250000U;//1000000U;

I also attach my modified project for your desired 250khz, it works Ok now.

Also provide the oscilloscope 250Kbps wave:

bit rate is correct!

Test platform: FRDM-KV11Z

Wish it helps you!

If you still have questions about it, please kindly let me know.

Kerry

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Re: Wrong baudrate flexcan demo "interrupt transfer" on FRDM-KV11Z SDK 2.7.0

robertoquilez — Wed, 13 May 2020 13:15:07 GMT

Thank you very much Kerry. It works!

Really valuable, I was stuck for a while.

Nevertheless I have difficulties understanding how I might had found the same values that you got following this step by step example:

Let's assume Baurate is 250Kbps and MCU clock is 10MHz
NBT x Prescaler = 40 (NBT = 8, Prescaler = 5)
Let's assume PROP_SEG is 1 because the CAN bus is really short.
NBT - 1Tq - PROP_SEG = 6
So PHASE_SEG1 and PHASE_SEG2 = 3

I don't know how do you get
#define PSEG1 4
#define PSEG2 1
#define PROPSEG 1

Can you explain your calculation please ?

Moreover in your previous post, baudrate 250K or 1M do not have any impact on PSEG1, PSEG2 or PROPSEG.

Re: Wrong baudrate flexcan demo "interrupt transfer" on FRDM-KV11Z SDK 2.7.0

kerryzhou — Thu, 14 May 2020 02:37:29 GMT

Hi Roberto Quilez，

Please read the KV11Z reference manual:

https://www.nxp.com/webapp/Download?colCode=KV11P64M75RM

Chapter 39.4.8.4 Protocol timing

You will find my configuration details.

1. 1Mbps, my configuration is

#define PSEG1 4
#define PSEG2 1
#define PROPSEG 1

Please note, Time segment 1= PSEG1+1, Time Segment 2= PSEG2+1

So, if you want to get 1Mbps, but your fCANCLK is external crystal 10Mhz.

What does it mean?

1Mbps= (10M/(PRESDIV+1))/(4+PROPSEG+PROPSEG+PSEG1).

If choose PRESDIV =0, no divide clock.

Then it means your 4+PROPSEG+PROPSEG+PSEG1= 10, then you need to check table 39-14, find item 1 is the proper one.

That's why I choose:

#define PSEG1 4
#define PSEG2 1
#define PROPSEG 1

2. 250Kbps

Now, why I don't modify the PSEG1, PSEG2, PROPSEG1?

Because my PRESDIV set the other data, if you debug the code and check the CAN_CTRL1[PRESDIV], you will find it is 3.

250Kbps=(10M/(PRESDIV+1))/(4+PROPSEG+PROPSEG+PSEG1).

=>250Kbps=(10M/(PRESDIV(3)+1))/(4+PROPSEG+PROPSEG+PSEG1).

Wish it helps you!

If you still have questions about it, please kindly let me know.

Kerry

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Re: Wrong baudrate flexcan demo "interrupt transfer" on FRDM-KV11Z SDK 2.7.0

robertoquilez — Thu, 14 May 2020 12:59:23 GMT

Kerry, thank you again for your rapide response.

I think there are some things in your post that do not match with what I see in the doct:

You wrote Time Segment 1 = PSEG1 + 1 but according to the reference manual it's PROPSEG + PSEG1 + 2
after you wrote (4+PROPSEG+PROPSEG+PSEG1) but I think you meant (4+PROPSEG+PSEG2+PSEG1)

With the formula:
4+PROPSEG+PSEG2+PSEG1 = 10
==> TS1 + TS2 = 9

How do you choose between line 1 or 2 of Table 39-14 ?
I mean TS1(7) + TS2(2) = TS1(6) + TS2(3) = 9

Re: Wrong baudrate flexcan demo "interrupt transfer" on FRDM-KV11Z SDK 2.7.0

kerryzhou — Fri, 15 May 2020 02:34:57 GMT

Hi Roberto Quilez,

Your understanding is wrong, seems you didn't check my picture which is from the KV11 RM:

bit time after clock divide is : SYNC_SEG+PROPSEG+PSEG1+2+PSEG2+1.

SYNC_SEG=1.

Then, you will know it is 4+PROPSEG+PSEG1+PSEG2

Please note PROPSEG,PSEG1,PSEG2 are the register value.

Time segment 1= PSEG1+1, Time Segment 2= PSEG2+1

The following picture is after +1

So 4+PROPSEG+PSEG2+PSEG1 = 10, it is 1+(Time segment 1=PSEG1+1)+(Time segment2=PSEG2+1)+(jump width=PSEG1 +1)

If PROPSEG=1 ,jump width=2, I want PSEG2+PSEG1+2 = 7, it is Time segment 1+ Time segment2=7.

So, if Time segment1 =5, Timesegment 2=2, it is 7, meet the demand.

Wish it really helps you to understand it.

Maybe you also need to double read the KV11 RM carefully.

If you still have questions about it, please kindly let me know.

Kerry

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Re: Wrong baudrate flexcan demo "interrupt transfer" on FRDM-KV11Z SDK 2.7.0

robertoquilez — Fri, 15 May 2020 07:55:09 GMT

Ok, you are right, thank you very much.

My misunderstanding was due to the first picture where we see:

Timer segment 1 = PROPSEG + PSEG1 + 2

When the formula to apply is:

Time segment 1= PSEG1+1.

Thank you very much for your support, again.