Is there a bug in FRDM_KEA128_RTC

elder_atom — Wed, 10 Oct 2018 12:21:06 GMT

It's showed as followed.

Re: Is there a bug in FRDM_KEA128_RTC

mjbcswitzerland — Mon, 02 Nov 2020 14:15:16 GMT

See whether the subroutine subtracts 1 from the passed values or not.
The pre-scaler value should indeed be 1 less than the divider value that is "required".

This is the corresponding initialisation code as used by the uTasker project on the KEA128:

        POWER_UP_ATOMIC(6, RTC);                                         // ensure the KE's RTC is powered
        rtc_interrupt_handler[iIRQ] = ((RTC_SETUP *)ptrSettings)->int_handler; // enter the handling interrupt
        fnEnterInterrupt(irq_RTC_OVERFLOW_ID, PRIORITY_RTC, (void (*)(void))_rtc_handler); // enter interrupt handler
        RTC_MOD = (((1000)/ RTC_CLOCK_PRESCALER_2) - 1);                 // set the match value for 1s
        RTC_SC = (RTC_SC_RTIE | RTC_SC_RTIF | _RTC_CLOCK_SOURCE | _RTC_PRESCALER); // clock the RTC from the defined clock source/pre-scaler and enable interrupt
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and the register values after the execution:

and so 9 is the value required.

Note however that the LPOCLK (1kHz) is quite inaccurate so deviations (or error) probably are not very noticeable.

Regards

Mark

Kinetis: http://www.utasker.com/kinetis.html
Kinetis KEA128:
- http://www.utasker.com/kinetis/TRK-KEA128.html
- http://www.utasker.com/kinetis/FRDM-KEAZ128Q80.html

For less questions and faster, cheaper developments: try uTasker for Kinetis

Re: Is there a bug in FRDM_KEA128_RTC

jingpan — Thu, 11 Oct 2018 07:24:55 GMT

Hi Li,

Yes, you're write. This value should be 9. The source code is not correct.

Regards,

Jing

topic Is there a bug in FRDM_KEA128_RTC in Kinetis Microcontrollers

Is there a bug in FRDM_KEA128_RTC

Re: Is there a bug in FRDM_KEA128_RTC

Re: Is there a bug in FRDM_KEA128_RTC