Confusion in example for KE watchdog

mjbcswitzerland — Tue, 08 Jul 2014 04:20:13 GMT

Hi All

With reference to the KE02 manual - the watchdog example code is given as:

This however gives a watchdog timeout of 59.395 seconds.

The reason for this is also given in the manual:

The code should therefore be either

WDOG_TOVALH = (unsigned char )(1000 >> 8);

WDOG_TOVALL = (unsigned char )(1000);

or WDOG_TOVAL = (unsigned short)((1000 >> 8) | (1000 << 8));

and then does give the advertised 1s timeout.

Regards

Mark

topic Confusion in example for KE watchdog in Kinetis Microcontrollers