<?xml version="1.0" encoding="UTF-8"?>
<rss xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#" xmlns:taxo="http://purl.org/rss/1.0/modules/taxonomy/" version="2.0">
  <channel>
    <title>i.MX Processors中的主题 Question about CCM_CACRR</title>
    <link>https://community.nxp.com/t5/i-MX-Processors/Question-about-CCM-CACRR/m-p/602135#M90597</link>
    <description>&lt;HTML&gt;&lt;HEAD&gt;&lt;/HEAD&gt;&lt;BODY&gt;&lt;P&gt;Hello Community&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;In page 829 of imx6sdl reference manual(IMX6SDLRM.pdf Rev.2),there is description for&amp;nbsp;arm_podf in&amp;nbsp;CCM_CACRR as bellow.&lt;/P&gt;&lt;P&gt;--------------&lt;/P&gt;&lt;P&gt;NOTE: If arm_freq_shift_divider is set to '1' then any new write to arm_podf will be held until&lt;BR /&gt;arm_clk_switch_req signal is asserted.&lt;/P&gt;&lt;P&gt;--------------&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;I searched arm_freq_shift_divider and arm_clk_switch_req in IMX6SDLRM.pdf, buf cannot find them in anywhere else.&lt;/P&gt;&lt;P&gt;So what does this NOTE mean?&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;Thank you!&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;ZongbiaoLiao&lt;/P&gt;&lt;/BODY&gt;&lt;/HTML&gt;</description>
    <pubDate>Mon, 12 Dec 2016 07:37:47 GMT</pubDate>
    <dc:creator>宗標廖</dc:creator>
    <dc:date>2016-12-12T07:37:47Z</dc:date>
    <item>
      <title>Question about CCM_CACRR</title>
      <link>https://community.nxp.com/t5/i-MX-Processors/Question-about-CCM-CACRR/m-p/602135#M90597</link>
      <description>&lt;HTML&gt;&lt;HEAD&gt;&lt;/HEAD&gt;&lt;BODY&gt;&lt;P&gt;Hello Community&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;In page 829 of imx6sdl reference manual(IMX6SDLRM.pdf Rev.2),there is description for&amp;nbsp;arm_podf in&amp;nbsp;CCM_CACRR as bellow.&lt;/P&gt;&lt;P&gt;--------------&lt;/P&gt;&lt;P&gt;NOTE: If arm_freq_shift_divider is set to '1' then any new write to arm_podf will be held until&lt;BR /&gt;arm_clk_switch_req signal is asserted.&lt;/P&gt;&lt;P&gt;--------------&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;I searched arm_freq_shift_divider and arm_clk_switch_req in IMX6SDLRM.pdf, buf cannot find them in anywhere else.&lt;/P&gt;&lt;P&gt;So what does this NOTE mean?&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;Thank you!&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;ZongbiaoLiao&lt;/P&gt;&lt;/BODY&gt;&lt;/HTML&gt;</description>
      <pubDate>Mon, 12 Dec 2016 07:37:47 GMT</pubDate>
      <guid>https://community.nxp.com/t5/i-MX-Processors/Question-about-CCM-CACRR/m-p/602135#M90597</guid>
      <dc:creator>宗標廖</dc:creator>
      <dc:date>2016-12-12T07:37:47Z</dc:date>
    </item>
    <item>
      <title>Re: Question about CCM_CACRR</title>
      <link>https://community.nxp.com/t5/i-MX-Processors/Question-about-CCM-CACRR/m-p/602136#M90598</link>
      <description>&lt;HTML&gt;&lt;HEAD&gt;&lt;/HEAD&gt;&lt;BODY&gt;&lt;P&gt;Hello&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P class=""&gt;&lt;SPAN class=""&gt;&amp;nbsp; This relates to bit “arm_podf_busy” of CCM Divider Handshake In-Process Register (CCM_CDHIPR) :&lt;/SPAN&gt;&lt;/P&gt;&lt;P class=""&gt;&lt;SPAN class=""&gt;&amp;nbsp;&lt;/SPAN&gt;&lt;/P&gt;&lt;P class=""&gt;&lt;SPAN class=""&gt;Busy indicator for “arm_podf”.&lt;/SPAN&gt;&lt;/P&gt;&lt;P class=""&gt;&lt;SPAN class=""&gt;&lt;BR /&gt;0 - divider is not busy and its value represents the actual division.&lt;/SPAN&gt;&lt;/P&gt;&lt;P class=""&gt;&lt;SPAN class=""&gt;&lt;BR /&gt;1 - divider is busy with handshake process with module. The value read in the divider represents the previous &lt;/SPAN&gt;&lt;/P&gt;&lt;P class=""&gt;&lt;SPAN class=""&gt;value of the division factor, and after the handshake the written value of the arm_podf will be applied.&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;Have a great day,&lt;BR /&gt;Yuri&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;-----------------------------------------------------------------------------------------------------------------------&lt;BR /&gt;Note: If this post answers your question, please click the Correct Answer button. Thank you!&lt;/P&gt;&lt;/BODY&gt;&lt;/HTML&gt;</description>
      <pubDate>Tue, 13 Dec 2016 08:18:11 GMT</pubDate>
      <guid>https://community.nxp.com/t5/i-MX-Processors/Question-about-CCM-CACRR/m-p/602136#M90598</guid>
      <dc:creator>Yuri</dc:creator>
      <dc:date>2016-12-13T08:18:11Z</dc:date>
    </item>
  </channel>
</rss>

