topic Re: How to add a new processor type to CW6.3 in Classic/Legacy CodeWarrior

How to add a new processor type to CW6.3

RobNijhuis — Mon, 12 Apr 2010 14:32:14 GMT

Hi,

For a new project I want to use the MCF52211, however I cannot select it as a target CPU in the Coldfire Processor settings panel (CW 6.3). Does anyone know how to add a new processortype?

Thanx,

Rob

Re: How to add a new processor type to CW6.3

CrasyCat — Mon, 12 Apr 2010 19:02:10 GMT

Hello

You cannot just add support for a new MCU like that.

In order for CodeWarrior MCU V6.3 to support a new MCU, you need to install a so called service pack for that MCU.

Available service packs can be downloaded from following URL:

http://www.freescale.com/webapp/sps/site/overview.jsp?nodeId=01272600617882

As far as I can tell there is no service pack for MCF52211 that can be installed on top of V6.3.

So in order to get support for that MCU you need to upgrade to the latest release of CodeWarrior.

CrasyCat

Re: How to add a new processor type to CW6.3

J2MEJediMaster — Mon, 12 Apr 2010 19:06:11 GMT

First, have you installed the latest service pack/updates for your version of CodeWarrior? Those can be obtained from this page.

---Tom

Re: How to add a new processor type to CW6.3

RobNijhuis — Wed, 14 Apr 2010 18:53:02 GMT

OK, thanks.

I already have installed the latest upgrades for version 6.3 so I gather I have to update to the latest verion (7.1??)

Where can I download the upgrade?

Will it work with my current license file?

Re: How to add a new processor type to CW6.3

J2MEJediMaster — Wed, 14 Apr 2010 19:37:12 GMT

You can download the free but limited Special Edition version of CodeWarrior from here and see if that solves your problem first.

---Tom

Re: How to add a new processor type to CW6.3

RobNijhuis — Thu, 15 Apr 2010 18:57:10 GMT

I just did. In the latest version the MCF52211 is supported, so this solves my problem. But how about the license, for CW6.3 we have a professional license, we'll need this for CW7.2 as well, can it be converted?

Thanx,

Rob