S32KのトピックS32K46 CAN 2.0 Sample point

S32K46 CAN 2.0 Sample point

玉敏111田 — Tue, 28 Jul 2020 01:14:49 GMT

I have not found the classical CAN (not FD CAN) sample point in S32K-RM.

So which method should be used to calculate classical CAN sample point below?

1).（1+TSEG1）/(1+TSEG1+TSEG2)

2. （1+TSEG1+PROP_SEG）/(1+TSEG1+PROP_SEG+TSEG2)

Re: S32K46 CAN 2.0 Sample point

Robin_Shen — Tue, 28 Jul 2020 02:40:04 GMT

Hi 玉敏111 田,

Please refer the Figure 55-7. Segments within the bit time (example using CTRL1 bit timing variables for Classical CAN format) of S32K-RM.

（1+TSEG1）/(1+TSEG1+TSEG2)

（1+PROPSEG+PSEG1+2）/(1+PROPSEG+PSEG1+2 + PSEG2+1)

By the way, the Processor Expert will calculate sample point automatically.

Best Regards,

Robin

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Re: S32K46 CAN 2.0 Sample point

玉敏111田 — Tue, 28 Jul 2020 02:59:31 GMT

Hi Robin,

Thanks for your reply.

When I calculated the sample point ,I found that the PSEG1 in Figure 55-7 was the same with Phase Buffer Segment 1 in S32K-RM rather than PSEG1 in S32K-RM.

Re: S32K46 CAN 2.0 Sample point

玉敏111田 — Tue, 28 Jul 2020 03:02:47 GMT

Re: S32K46 CAN 2.0 Sample point

Robin_Shen — Wed, 29 Jul 2020 07:39:37 GMT

Sorry

I didn't understand what you mean.

For example:

.propSeg = 7,
.phaseSeg1 = 4,
.phaseSeg2 = 1,

sample point =（1+Time Segment 1）/(1+Time Segment 1+Time Segment 2)=（1+PROPSEG+PSEG1+2）/(1+PROPSEG+PSEG1+2 + PSEG2+1) = (1+7+4+2)/ (1+7+4+2 +1+1)=87.5%

Best Regards,

Robin