Can not enter the CAN Tx/Rx Interrupt.

liufei — Tue, 21 Jun 2022 02:37:04 GMT

Hello，

I make very simple CAN TX test used board with S32K148 144pin.can write function return OK,But Can not enter the CAN Tx/Rx Interrupt.

I set MCAL by EB 24.0.1,Can Rx Processing Type,Can Tx Processing Type and Can BusOff Processing Type set all to interrupt.Then I also set interrupt setting in my test code beacuse without OS,like this:

/*
* can_test.c
*
* Created on: 2022年6月9日
* Author: liu-fei
*/
#include "Mcu.h"
#include "Port.h"
#include "Mcl.h"
#include "Spi.h"
#include "Dio.h"
#include "S32K148.h"
#include "startup.h"
#include "string.h"
#include "Can.h"
#include "stdio.h"
#include "Os_Hal_ContextInt.h"
#include "CanIf_Cbk.h"

#define MCAL_CAN_TEST
#ifdef MCAL_CAN_TEST

Can_PduType PduInfo_test;

/**< Variables which contains Can PDU data used in Can transmission */
uint8 CanApp_InputData[16U] =
{0xA1, 0x1A, 0xFF, 0xFF, 0xC1, 0x1C, 0xB1, 0x1B,
//0xA2, 0x2A, 0xFF, 0xFF, 0xC2, 0x2C, 0xB2, 0x2B,
//0xA3, 0x3A, 0xFF, 0xFF, 0xC3, 0x3C, 0xB3, 0x3B,
//0xA4, 0x4A, 0xFF, 0xFF, 0xC4, 0x4C, 0xB4, 0x4B,
//0xA5, 0x5A, 0xFF, 0xFF, 0xC5, 0x5C, 0xB5, 0x5B,
//0xA6, 0x6A, 0xFF, 0xFF, 0xC6, 0x6C, 0xB6, 0x6B,
//0xA7, 0x7A, 0xFF, 0xFF, 0xC7, 0x7C, 0xB7, 0x7B,
0xA8, 0x8A, 0xFF, 0xFF, 0xC8, 0x8C, 0xB8, 0x8B};

//ISR(Can_IsrFCA_BO);
ISR(Can_IsrFCB_MB_00_15);

uint32 counter = 0;
void Device_CAN_TEST(void)
{

Can_ReturnType canRet;
isr_t func_p;

Dio_LevelType channel_PTE_25;

Dio_WriteChannel(DioConf_DioChannel_PTE_25,1);//CANTRCV_TRCVMODE_NORMAL:TJA1043_EN

channel_PTE_25 = Dio_ReadChannel(DioConf_DioChannel_PTE_25);

Dio_LevelType channel_PTA_11;

Dio_WriteChannel(DioConf_DioChannel_PTA_11,1);//CANTRCV_TRCVMODE_NORMAL:TJA1043_STB_N

channel_PTA_11 = Dio_ReadChannel(DioConf_DioChannel_PTA_11);

//Tx/Rx/Fifo Message Buffer Interrupt.
INT_installHandler(CAN1_ORed_0_15_MB_IRQn, Can_IsrFCB_MB_00_15, &func_p);

Os_Hal_NvicEnableIRQ(CAN1_ORed_0_15_MB_IRQn);

Os_Hal_NvicSetPriority(CAN1_ORed_0_15_MB_IRQn, 0x10);

PduInfo_test.length = 16U;

PduInfo_test.sdu = &CanApp_InputData[0U];

PduInfo_test.swPduHandle = 1; //L-PDU handle of CAN L-PDU successfully transmitted.This ID specifies the corresponding CAN L-PDU ID
// and implicitly the CAN Driver instance as well as the
// corresponding CAN controller device.

PduInfo_test.id = 0xA0 | 0x40000000U;//dentifies the HRH and its corresponding CAN Controller

Can_SetControllerMode(0,CAN_T_START);

#if 0
while(1)
{
canRet = Can_Write(0x1U, &PduInfo_test);
delay(5000000);
Can_SetControllerMode(0,CAN_T_START);

if(canRet == CAN_OK)
printf("CAN send OK！");

if(canRet == CAN_BUSY)
printf("CAN send NG！");

}
#else

canRet = Can_Write(0x1U, &PduInfo_test);

if(canRet == CAN_OK)
printf("CAN send OK！");

if(canRet == CAN_BUSY)
printf("CAN send NG！");
#endif

}
#endif

Could you please give me some advise，Thank you！

Best regards，

Liufei

Re: Can not enter the CAN Tx/Rx Interrupt.

cuongnguyenphu — Thu, 23 Jun 2022 02:06:45 GMT

Hi @liufei ,
Can you let us know which platform version you're working on? (you can capture information on Publish Information tab)
Be side of that, can you share me your Can config on EB Tresos?

Re: Can not enter the CAN Tx/Rx Interrupt.

liufei — Thu, 23 Jun 2022 02:51:43 GMT

Hi cuongnguyenphu,

Thanks for reply,I have resolved this problem,

but I have some question about Can config setting,like this,

Can Controller Prescaller of description:

Prescaler = FreqCanClk / FreqTq; FreqTq = 1 / CanControllerTimeQuanta .

What dose CanControllerTimeQuanta mean？

FreqTq is equal 1/Tq? right?

CanControllerTimeQuanta is same to Tq?

Could you please answer it,thank you very much.

Best Regards,

Liufei

Re: Can not enter the CAN Tx/Rx Interrupt.

cuongnguyenphu — Mon, 27 Jun 2022 08:49:46 GMT

Hi @liufei
As per Reference manual:
1. What dose CanControllerTimeQuanta mean？> Time-Quantum = one Sclock period. CanControllerTimeQuanta means Sclock in below diagram. You can check more detail in Reference manual
2. FreqTq is equal 1/ Tq ? right? > Yes, It's correct
3. CanControllerTimeQuanta is same to Tq? > Yes, It's correct

Additional information:

Re: Can not enter the CAN Tx/Rx Interrupt.

liufei — Mon, 27 Jun 2022 10:30:09 GMT

Hi cuongnguyenphu,

Thank you very much!

BestRegards,

Liu

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