https://community.nxp.com/t5/Power-Management/TJA1028-VCC-OutputCurrent/m-p/1813321#M3310 <P>Hi</P><P>The translation was incorrect.</P><P>①I would like to know the current that TJA1028 VCC can output.<BR />Please tell me how many mA can be output when the input is 16V, the output is 5V, and the temperature is 85℃.<BR />②The power supply data sheet contains a graph with power on the vertical axis and temperature on the horizontal axis.<BR />Since it was not described in TJA1028, could you please tell me how to calculate the power and temperature and the graph?<BR />③ Loss = (input voltage - output voltage) / output current?<BR />I guess it fits.</P><P>best regard</P> Thu, 22 Feb 2024 05:13:42 GMT ban45 2024-02-22T05:13:42Z https://community.nxp.com/t5/Power-Management/TJA1028-VCC-OutputCurrent/m-p/1813321#M3310 <P>Hi</P><P>The translation was incorrect.</P><P>①I would like to know the current that TJA1028 VCC can output.<BR />Please tell me how many mA can be output when the input is 16V, the output is 5V, and the temperature is 85℃.<BR />②The power supply data sheet contains a graph with power on the vertical axis and temperature on the horizontal axis.<BR />Since it was not described in TJA1028, could you please tell me how to calculate the power and temperature and the graph?<BR />③ Loss = (input voltage - output voltage) / output current?<BR />I guess it fits.</P><P>best regard</P> Thu, 22 Feb 2024 05:13:42 GMT https://community.nxp.com/t5/Power-Management/TJA1028-VCC-OutputCurrent/m-p/1813321#M3310 ban45 2024-02-22T05:13:42Z https://community.nxp.com/t5/Power-Management/TJA1028-VCC-OutputCurrent/m-p/1813398#M3312 <P>Could you please post your question using English?</P> Thu, 22 Feb 2024 05:02:39 GMT https://community.nxp.com/t5/Power-Management/TJA1028-VCC-OutputCurrent/m-p/1813398#M3312 guoweisun 2024-02-22T05:02:39Z https://community.nxp.com/t5/Power-Management/TJA1028-VCC-OutputCurrent/m-p/1813455#M3313 <UL> <LI>I would like to know the current that TJA1028 VCC can output.<BR />Please tell me how many mA can be output when the input is 16V, the output is 5V, and the temperature is 85℃.</LI> </UL> <P>[gw]70mA can be supported.</P> <P>②The power supply data sheet contains a graph with power on the vertical axis and temperature on the horizontal axis.<BR />Since it was not described in TJA1028, could you please tell me how to calculate the power and temperature and the graph?</P> <P>[gw]<SPAN> <A href="https://www.nxp.com/products/power-management/pmics-and-sbcs/system-basis-chips/lin-transceiver-with-integrated-voltage-regulator:TJA1028#documentation" target="_blank">TJA1028 | LIN Transceiver with Integrated Voltage Regulator | NXP Semiconductors</A></SPAN></P> <P><span class="lia-inline-image-display-wrapper lia-image-align-inline" image-alt="guoweisun_0-1708582305077.png" style="width: 400px;"><img src="https://community.nxp.com/t5/image/serverpage/image-id/264457iEA625EA0D363EC3F/image-size/medium?v=v2&amp;px=400" role="button" title="guoweisun_0-1708582305077.png" alt="guoweisun_0-1708582305077.png" /></span></P> <P>&nbsp;</P> <P>You can download this power dissipation calculator for getting more info.<BR />③ Loss = (input voltage - output voltage) / output current?</P> <P>[gw]should be VIN*IIN -VOUT*IOUT</P> Thu, 22 Feb 2024 06:11:51 GMT https://community.nxp.com/t5/Power-Management/TJA1028-VCC-OutputCurrent/m-p/1813455#M3313 guoweisun 2024-02-22T06:11:51Z