Problem to send 13 bit LIN Break!

mehdializadeh — Mon, 26 Dec 2022 11:20:46 GMT

Hi
I use mc9s08dz96. I wrote the corresponding registers to create a break at the beginning of the data LIN frame. The data frame is sent correctly, but the problem is that the break part is not 13 bits. I set the break registers like this:

if (SCI1S1_TDRE == 0U) { return ERR_TXFULL; } SCI1C2_SBK = 0x01U; SCI1C2_SBK = 0x00U;

Then I send 0x55 and ID:

while(1){ if (SCI1S1_TDRE == 0U) { return ERR_TXFULL; } SCI1C2_SBK = 0x01U; SCI1C2_SBK = 0x00U; delayy(10); c=AS1_SendChar(Sync_); delayy(10); c=AS1_SendChar(ID_); delayy(333); }

I initialized these registers:

void AS1_Init(void) { SerFlag = 0x00U; /* Reset flags */ /* SCI1C1: LOOPS=1,SCISWAI=0,Rsrc=1,M=0,WAKE=1,ILT=0,PE=0,PT=0 */ setReg8(SCI1C1, 0xA8U); /* Configure the SCI */ /* SCI1C3: R8=0,T8=0,TXDIR=1,TXINV=0,ORIE=0,NEIE=0,FEIE=0,PEIE=0 */ setReg8(SCI1C3, 0x20U); /* Disable error interrupts */ /* SCI1C2: TIE=0,TCIE=0,RIE=0,ILIE=0,TE=0,RE=0,RWU=0,SBK=0 */ setReg8(SCI1C2, 0x00U); /* Disable all interrupts */ /* SCI1S2: LBKDIF=0,RXEDGIF=0,??=0,RXINV=0,RWUID=0,BRK13=1,LBKDE=0,RAF=0 */ setReg8(SCI1S2, 0x04U); SCI1BDH = 0x00U; /* Set high divisor register (enable device) */ SCI1BDL = 0x1AU; /* Set low divisor register (enable device) */ SCI1C2_TE = 0x01U; /* Enable transmitter */ SCI1C2_RE = 0x01U;}

BRK13 defines for us that the break length is 13. If you have noticed in the registers above, I have set it.

setReg8(SCI1S2, 0x04U);

Finally, the frame LIN is like this:

Break is correctly sent, also 0x55, 0x34 for sync and ID, respectively. But the break length is not 13 bits. what is the reason?

topic Problem to send 13 bit LIN Break! in 8-bit Microcontrollers

Problem to send 13 bit LIN Break!