8-bit Microcontrollers中的主题 HSC08 memory Security and rewrite problems

HSC08 memory Security and rewrite problems

jy — Mon, 05 Oct 2009 14:51:12 GMT

Hi sir,

const volatile unsigned char NVPROT_INIT @0x0000FFBD = 0xDE;
const volatile unsigned char NVOPT_INIT @0x0000FFBF = 0xF0;

void IC_Protect_Disable(void)
{
unsigned int data_addr =0xFFB0;

FCNFG_KEYACC = 0x1;
*(unsigned char *)data_addr = 0x0;
data_addr++;
*(unsigned char *)data_addr = 0x1;
data_addr++;
*(unsigned char *)data_addr = 0x2;
data_addr++;
*(unsigned char *)data_addr = 0x3;
data_addr++;

*(unsigned char *)data_addr = 0x4;
data_addr++;
*(unsigned char *)data_addr = 0x5;
data_addr++;
*(unsigned char *)data_addr = 0x6;
data_addr++;
*(unsigned char *)data_addr = 0x7;
data_addr++;
FCNFG_KEYACC = 0x0;
}

==============================================

I used JM8 in my project. and the protect blocks from E000~FFFF .

Inside that blocks, rewrite process is no allow due to scurity.

but when i call "IC_Protect_Disable" show as above, the block is also unlock,

how can i do ?!

Re: HSC08 memory Security and rewrite problems

kef — Mon, 05 Oct 2009 15:40:06 GMT

1. Flash is not readable while KEYACC is set. Thus your IC_Protect_Disable() routine should run from RAM.

2. Backdoor unsecure is supposed to allow R/W access via BDM pin. Backdoor unsecure doesn't disengage flash write protection.

Re: HSC08 memory Security and rewrite problems

tonyp — Mon, 05 Oct 2009 17:00:21 GMT

3. Values 0x0000 and 0xFFFF are not permitted as backdoor keys (at least for some parts, like the QE128).