8-bit MicrocontrollersのトピックRe: how to use the adc interrupt

how to use the adc interrupt - MC68HC908MR

quimey — Fri, 16 Jan 2009 08:36:06 GMT

hello micromans i need to use the adc interrupt but is no working

this code would be to turn on the pta01 way do not work???

void init_adc(void){

ADSCR_ADCO=1;/*CONVERSION continua*/

ADSCR_ADCH0=1;/*ELIJO ATD1 PIN 63*/
ADSCR_ADCH1=0;
ADSCR_ADCH2=0;
ADSCR_ADCH3=0;
ADSCR_ADCH4=0;

ADCLK_ADIV2=1;/*ELIJO EL PRESCALER EN 8 PARA TENER APROX 0,5MHZ DE CLOCK DE ADC*/
ADCLK_ADIV1=0;/*8,9MHZ CRISTAL*/
ADCLK_ADIV0=0;

ADCLK_MODE1=0;/*ELIJO TRUNCAR A 8 BIT*/
ADCLK_MODE0=0;
ADSCR_AIEN=1;
}

void init_output(void){
DDRA=0b00000010;
}

interrupt 17 void lecturaadc(void)
{
#pragma TRAP_PROC SAVE_REGS
ADC=ADRL;
PTA_PTA1=1;
}

Added p/n to subject

Message Edited by NLFSJ on 2009-01-26 09:26 AM

Re: how to use the adc interrupt

Ake — Fri, 16 Jan 2009 17:52:36 GMT

Hi,

Which MCU are you using?

I looked but could not find any 9S08 with an ADC interrupt vector at 17.

Regards,

Ake

Re: how to use the adc interrupt

denny_george — Fri, 16 Jan 2009 21:42:39 GMT

Hi Ake,

He seems to be using MC68HC908MR .

http://forums.freescale.com/freescale/board/message?board.id=8BITCOMM&thread.id=13035

I need your help in solving my problem: "Bus clock independent code snippet"

http://forums.freescale.com/freescale/board/message?board.id=8BITCOMM&thread.id=13054

Message Edited by Geo*** on 2009-01-16 01:44 PM

Re: how to use the adc interrupt

quimey — Sat, 17 Jan 2009 20:16:04 GMT

I use the hc08 mr32 mcu

rewards

Quimey

Re: how to use the adc interrupt

Ake — Wed, 21 Jan 2009 18:13:01 GMT

Hi,

I tried it on an ICS08MR board and after some small changes, it seems to work.

Here is the code I have changed:

/******************************************************************
* InitADC - initialize the ADC
*
* Calling convention:
* InitADC()
*
* Returns: nothing
******************************************************************/
void InitADC(void) {
ADSCR = 0; //stop conversion

#if ADC_8BIT
ADCLK = ADCLK_ADICLK_MASK; //internal bus clock/1, 8 bit result,
#else
ADCLK = ADCLK_ADICLK_MASK
         |ADCLK_MODE0_MASK; //internal bus clock/1, right justified 10 bit result
                            //divide by 4, right justified

#endif
        ADSCR_ADCH0=1;       //read ATD1 PIN 63
        ADSCR_ADCO=1;       //continous conversion
        ADCLK_ADIV2 = 1;   //divide input clock by 16
        ADSCR_AIEN = 1;      //enable the interrupts
};

/******************************************************************
* main - entry point to this program
*
* Calling convention:
* main()
*
* Returns: nothing
******************************************************************/
void main(void) {
CONFIG_COPD = 1; // turn off the COP

        InitIO();
        InitPLL();


        InitADC();
        EnableInterrupts; /* enable interrupts */

        for(; {
               asm nop;

} /* loop forever */
};

/******************************************************************
* Interrupt for the ADC
*
* Calling convention:
* lecturaadc()
*
* Returns: nothing
******************************************************************/
interrupt VectorNumber_ADC void lecturaadc(void)
{
ADCresult = ADRL; //get and store ADC result
PTC_PTC2 ^= 1;
}

I haven't checked the program but it seems to work. The PTC2 pin toggled at 4.8 kHz, which means that the interrupt was running at about every mS.

Regards,

Ake