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    <title>topic 9S08DZ Crystal oscillator circuit / resistor RF in 8-bit Microcontrollers</title>
    <link>https://community.nxp.com/t5/8-bit-Microcontrollers/9S08DZ-Crystal-oscillator-circuit-resistor-RF/m-p/214195#M18540</link>
    <description>&lt;HTML&gt;&lt;HEAD&gt;&lt;/HEAD&gt;&lt;BODY&gt;&lt;SPAN&gt;Hello,&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;generally in a Pierce oscillator configuration (MHz range)&amp;nbsp; with a quartz crystal connected to the MCU the design sometimes calls for an external 'feedback resistor' in the range of 1 to 10 Meg-Ohms. On some MCUs this resistor is already incorporated (e.g. the MC68HC05 datasheet says 'An internal feedback resistor is provided on-chip between OSC1 and OSC2') but in the 9S08DZ-series this resistor is externally needed - see page 381 in data sheet 'MC9S08DZ60 Series Rev.4'.&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;If the design also needs the drive level limiting resistor RS up to know I was only familiar with the feedback resistor RF being connected to the XTAL-pins of the MCU but not in parallel with the crystal (as shown in the 9S08DZ data sheet). For me this looks like a drawing error - in other osc circuits I never saw RF connected this way.&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;Does anyone in this group has some background explanation why this circuit should be correct?&lt;/SPAN&gt;&lt;BR /&gt;&lt;SPAN&gt;(or be technically equivalent to the version with RF parallel to the MCU pins)&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;I am well aware that this question only arises if RS is present. In an application where the quartz current needs not to be limited by a series resistor then RS equals zero ohms and RF has direct connection to both MCU xtal pins.&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;Thanks for any help.&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;-Roland&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;/BODY&gt;&lt;/HTML&gt;</description>
    <pubDate>Thu, 08 Jan 2009 00:25:44 GMT</pubDate>
    <dc:creator>Cantalis</dc:creator>
    <dc:date>2009-01-08T00:25:44Z</dc:date>
    <item>
      <title>9S08DZ Crystal oscillator circuit / resistor RF</title>
      <link>https://community.nxp.com/t5/8-bit-Microcontrollers/9S08DZ-Crystal-oscillator-circuit-resistor-RF/m-p/214195#M18540</link>
      <description>&lt;HTML&gt;&lt;HEAD&gt;&lt;/HEAD&gt;&lt;BODY&gt;&lt;SPAN&gt;Hello,&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;generally in a Pierce oscillator configuration (MHz range)&amp;nbsp; with a quartz crystal connected to the MCU the design sometimes calls for an external 'feedback resistor' in the range of 1 to 10 Meg-Ohms. On some MCUs this resistor is already incorporated (e.g. the MC68HC05 datasheet says 'An internal feedback resistor is provided on-chip between OSC1 and OSC2') but in the 9S08DZ-series this resistor is externally needed - see page 381 in data sheet 'MC9S08DZ60 Series Rev.4'.&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;If the design also needs the drive level limiting resistor RS up to know I was only familiar with the feedback resistor RF being connected to the XTAL-pins of the MCU but not in parallel with the crystal (as shown in the 9S08DZ data sheet). For me this looks like a drawing error - in other osc circuits I never saw RF connected this way.&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;Does anyone in this group has some background explanation why this circuit should be correct?&lt;/SPAN&gt;&lt;BR /&gt;&lt;SPAN&gt;(or be technically equivalent to the version with RF parallel to the MCU pins)&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;I am well aware that this question only arises if RS is present. In an application where the quartz current needs not to be limited by a series resistor then RS equals zero ohms and RF has direct connection to both MCU xtal pins.&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;Thanks for any help.&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;-Roland&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;/BODY&gt;&lt;/HTML&gt;</description>
      <pubDate>Thu, 08 Jan 2009 00:25:44 GMT</pubDate>
      <guid>https://community.nxp.com/t5/8-bit-Microcontrollers/9S08DZ-Crystal-oscillator-circuit-resistor-RF/m-p/214195#M18540</guid>
      <dc:creator>Cantalis</dc:creator>
      <dc:date>2009-01-08T00:25:44Z</dc:date>
    </item>
    <item>
      <title>Re: 9S08DZ Crystal oscillator circuit / resistor RF</title>
      <link>https://community.nxp.com/t5/8-bit-Microcontrollers/9S08DZ-Crystal-oscillator-circuit-resistor-RF/m-p/214196#M18541</link>
      <description>&lt;HTML&gt;&lt;HEAD&gt;&lt;/HEAD&gt;&lt;BODY&gt;Hello and welcome to the fora, Cantalis,&lt;BR /&gt;&lt;BR /&gt;The circuit, as presented in the referenced manual, is correct. This same circuit is shown in virtually every one of Freescale's MPU datasheets. Whilst it varies from the &lt;A href="http://en.wikipedia.org/wiki/Pierce_oscillator" rel="nofollow" target="_blank"&gt;normal configuration&lt;/A&gt; slightly, it should make little difference to its operation due to the relative values of the two resistors.&lt;BR /&gt;&lt;BR /&gt;&lt;DIV&gt;&lt;/DIV&gt;&lt;/BODY&gt;&lt;/HTML&gt;</description>
      <pubDate>Sun, 11 Jan 2009 05:51:11 GMT</pubDate>
      <guid>https://community.nxp.com/t5/8-bit-Microcontrollers/9S08DZ-Crystal-oscillator-circuit-resistor-RF/m-p/214196#M18541</guid>
      <dc:creator>peg</dc:creator>
      <dc:date>2009-01-11T05:51:11Z</dc:date>
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