ADC code for MC9S08QG8, please help

Magic86 — Sun, 14 Feb 2010 19:16:01 GMT

Hi there. I have a demo board for MC9S08QG8, its not an official one. Anyway it has a potentiometer connected to channel 0 PTA0.

All Im trying to do is output the adc value to 8 lights connected to port B. Can you please correct my code? Im using interrupts to read the data after the conversion is completed:

<code>

#include <hidef.h> /* for EnableInterrupts macro */

#include "derivative.h" /* include peripheral declarations */

void adcISR(void);

volatile unsigned char result;

void main(void) {

EnableInterrupts; /* enable interrupts */

SOPT1_COPE=0;

ADCSC1=0x40; //interrupst enable, one conversion, input channel 0

ADCSC2=0x00; //software trigger, no comparison

APCTL1=0x01; //pin AD0 I/O disabled

ADCCFG=0x90; //low power, bus clock, long sample, 8bit mode

PTBDD=0xFF; //Set port b as output

PTBPE=0x00; //pull-up resistors

for(;;

}

interrupt 19 void adcISR(void) {

PTBD=ADCRL; // read the ADC result and put it onto port B

return;

}

</code>

Thank you in advance.

Re: ADC code for MC9S08QG8, please help

bigmac — Tue, 16 Feb 2010 20:08:10 GMT

Hello,

You do not say what specific problem you are experiencing.

However, keep in mind that the ADC conversion is started by a write to ADSC1 register. Therefore the other ADC registers require to be initialised prior to starting the conversion. The ADSC1 register should be the last one to be written.

This does not currently seem to be the case, so the result of the first (and only) conversion is likely to be incorrect.

Regards,

Mac

8-bit MicrocontrollersのトピックADC code for MC9S08QG8, please help

ADC code for MC9S08QG8, please help

Re: ADC code for MC9S08QG8, please help